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Kitty [74]
2 years ago
7

This is just a review!!!!!!! help!!!!!!!!!! Question is on image below.

Mathematics
2 answers:
sergey [27]2 years ago
5 0

Answer:

I don't know but use this app on your phone called mw  and it should help

Step-by-step explanation:

dmitriy555 [2]2 years ago
5 0
104 degrees !!! If 3 is 76, this makes angle 1 : 76 degrees as well because they are vertical. Now we can solve for angle 2 which is 180-76 = 104 and this is also vertical so it is equivalent to 4.
You might be interested in
Transformation of quadratic functions
Kitty [74]

Answer:

g(x) = a(x − h)2 + k, where a ≠ 0.

Step-by-step explanation:

The parent function of the quadratic family is f(x) = x2. A transformation of the graph of the parent function is represented by the function g(x) = a(x − h)2 + k, where a ≠ 0.

6 0
2 years ago
WHAT IS THE SQUARE ROOT OF 225
ludmilkaskok [199]
The square root of 225 is 15 :)
3 0
3 years ago
Read 2 more answers
Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
2 years ago
Directions: Solve these equations by using addition. You will need to use your fraction and decimal skills to solve these
Marina CMI [18]
One simple way to approach this is to subtract the number that DOESN’T have the variable with the solution by the sum.
Lets use problem 1 as the example:
1.) N+8=13
In this case, we subtract 13 by 8 and get 5, therefore N= 5.

2.) B+17=62
62-17= 45
B= 45

3.) X+5/6= 7/16
7/16-5/6= -19/48
X= -19/48

4.) y+1/7=5/8
5/8-1/7= 27/56
Y= 27/56

5.) 14+y=69
69-14=55
Y=55

6.) c+3.6=4.9
4.9-3.6=1.3
C= 1.3

Now for the word problems:
Lets use 7 as the example-
7.) a number increased by 19 is equal to 221.
Since we don’t know the number being increased by 19, that will be our variable. It will be re-written as so:

N + 19 = 221

Where N is the unknown number.

Using the same method of subtracting by the sum and the number that’s not the variable, we’ll get the solution to N
221-19= 202
N= 202

8.) N + 1 2/3 = 8
8 - 1 2/3 = 19/3= 6 1/3
N= 6 1/3

I really hope this helps
6 0
2 years ago
At a basketball game, a vender sold a combined total of 223 sodas and hot dogs. The number of hot dogs sold was 57 less than the
AnnZ [28]

Answer: 140 Hot dogs and 83 sodas.


Step-by-step explanation:

Alright, so we will say that h = hot dogs and s = sodas.

h + s = 223

I have used the guess and test strategy to get:

h = 140

140 - 57 = 83

s = 83

Check: 83 + 140 = 223

4 0
2 years ago
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