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4 years ago

21$ with 8.5% tax.How much

1 answer:

5 0

First find the amount of tax by multiplying 21 × 8.5%.

.085 × 21 = 1.785 = 1.79 (rounded)

Now add the tax back into the price...

21 + 1.79 = $22.79

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Greg has 15 marbles.He puts them in 3 equal group How many marbles are each group

sergeinik [125]

15/3=5
5 would be the answer since 15 can be evenly divided by 3

6 0

3 years ago

Read 2 more answers

Plz help, will give brainiest

Tems11 [23]

Answer:

4x^2 + 8x + 4

4(x^2 + 2x + 1) - remove GCF of 4

4(x + 1)(x + 1) - factor

4(x + 1)^2 - collect like terms

Step-by-step explanation:

Then also expand it out by distributing:

21x^3 + 35x²

Form 1:

21x^3 + 35x² - unfactored

Form 2:

7x²(3x + 5) - factored with GCF of 7x² brought to the front

Update:

You could also multiply two binomials and make a quadratic.

Example:

(7x + 2)(3x + 5)

7x(3x + 5) + 2(3x + 5)

= 21x² + 35x + 6x + 10

= 21x² + 41x + 10

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3 years ago

What is the solution to 2x+10y=-14 and x+5y=-7 answer using elimination with steps

VikaD [51]

Answer:

ty for the free points

Step-by-step explanation:

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3 years ago

Which table represents a linear function?

kykrilka [37]

Answer:

Option 3 (C)

Step-by-step explanation:

It is the only one that changes the same amount every time ( times 2 )

7 0

3 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago