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valentinak56 [21]
3 years ago
6

8.

Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0
Center c and a scale factor of 2
zlopas [31]3 years ago
4 0

Answer: C) center C and scale factor 2

Step-by-step explanation:

Since, The center of a dilation is a fixed point in the plane about which all points are expanded or contracted.

Therefore, By the given diagram we can say that the image is dilated along the point C.

⇒ C is the center of the dilation.

Since, for the given diagram the scale factor of dilation = \frac{C'A'}{CA} = \frac{10}{5} = 2

Thus, the scale factor is 2.

Therefore, Option C is correct.

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On a coordinate plane, what is the distance between the points at (1,9) and the point (4, 9)?
sammy [17]

If you draw out a coordinate plane you will see that they , on their Y access, are both nine witch means that they a horizontal line so all you have to do is subtract the x access witch is 3.

hope this helped


4 0
3 years ago
6.23+(-12.49)-2.6<br> What's the answer?
Mila [183]
6.23+ -12.49 -2.6= 6.23+ -12.49+ -2.6
-6.26+-2.6= -8.86
4 0
3 years ago
Read 2 more answers
What can be measured in nanometers?
Art [367]

Nanometers are a really small measurement, one billionth of a meter, I believe.

So nanometers is used to describe tiny stuff, like atoms of a water molecule, and waves of  light.

3 0
3 years ago
2 Probability and Stats questions!!
mart [117]
 1) To find the confidence interval 
the sample mean x = 38     σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05   
</span><span>α/2 = 0.025   </span>Z(α/2) = z0.025  
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample

</span></span>2) To find the confidence interval  <span>
<span>the sample mean x = </span>76     σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95 
so α = 1 – CL = 0.05   
α/2 = 0.025   Z(α/2) = z0.025 
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975 
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span>  x + EBM = 76 + 3.2575 = 79.2575 <span> 
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span> the 95% confidence interval for the mean of the sample</span></span>
5 0
3 years ago
I will give Brainiest if you are right
Dafna11 [192]

Answer:

H is the answer because 15/32 is the largest so it is in the back

5 0
3 years ago
Read 2 more answers
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