Please help!! im having a really hard time with this!!

Find an equation for the surface consisting of all points P in the three-dimensional space such that the distance from P to the

erik [133]

Answer:

x^2 +4y +z = 1

Step-by-step explanation:

Surface consisting of all points P to point (0,1,0) been equal to the plane y =1

given point, p (x,y,z ) the distance from P to the plane (y)

| y -1 |

attached is the remaining part of the solution

8 0

2 years ago

A triangle has side lengths measuring 3x cm, 7x cm, and hcm Which expression describes the possible values of h, in cm?

GREYUIT [131]

Answer:

OLX is your answer if 10 x

4 0

2 years ago

Please help!! I'm super confused :(

Kobotan [32]

Answer:

90 lb/1 x 0.45 = 40.5

Step-by-step explanation:

To convert pounds to kilograms you would have to multiply the pounds by 0.45. So you have to multiply 90 by 0.45.

5 0

2 years ago

What is the equation of a line perpendicular to y=-2/5X-1 that passes through (2,-8)

AysviL [449]

Answer:

$y=\frac{5}{2}x-13$

Step-by-step explanation:

Given the equation

$y=-\frac{2}{5}x-1$

comparing the equation with the slope-intercept form $y=mx+b$

Here,

m is the slope

b is the intercept

so the slope of the line is m = -2/5

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line,

so the slope of the perpendicular line will be: 5/2

Therefore, the point-slope form of the equation of the perpendicular line that goes through (2,-8) is:

$y-y_1=m\left(x-x_1\right)$

$y-\left(-8\right)=\frac{5}{2}\left(x-2\right)$

$y+8=\frac{5}{2}\left(x-2\right)$

subtract 8 from both sides

$y+8-8=\frac{5}{2}\left(x-2\right)-8$

$y=\frac{5}{2}x-13$

8 0

2 years ago

Can someone please write this as a single logarithm and show work please and thank you

Mazyrski [523]

Answer:

$log_b(w^3y^4)$

Step-by-step explanation:

To write the expression as a single logarithm, or condense it, use the properties of logarithms.

1) The power property of logarithms states that $log_ax^r = rlog_ax$ . In other words, the exponent within a logarithm can be brought out in front so it's multiplied by the logarithm. This means that the number in front of the logarithm can also be brought inside the logarithm as an exponent.

So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:

$3log_bw+4log_by\\=log_bw^3+log_by^4$

2) The product property of logarithms states that $log_axy = log_ax+log_ay$ . In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of $w^3$ and $y^4$ . Apply the property as seen below and find the final answer.

$log_bw^3+log_by^4\\=log_b(w^3y^4)$

So, the answer is $log_b(w^3y^4)$ .

4 0

2 years ago