Your answer is "happy" based on <span>mood-dependent memory research they conducted.</span>
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
Answer:
Step-by-step explanation:
Solve the inequality 5x − 4y > 20 for y, as follows: Subtract 5x from both sides, obtaining:
-4y > 20 - 5x;
Then divide all terms by -4:
y < -5 +(5/4)x, where the direction of the inequality sign has been reversed because of division by a negative quantity.
Temporarily replace the < symbol with = obtaining y = -5 +(5/4)x. Now choose at least three x values and find the corresponding y values. For example:
x y = -5 +(5/4)x
0 -5
4 0
-8 -15
Now plot these three points (0, -5), (4, 0) and (-8, -15). Draw a dashed line through them. Because of the < symbol in y < -5 +(5/4)x, shade the area underneath the dashed line.
Ricky jogged 6 miles on tuesday and 6 miles on friday
<em><u>Solution:</u></em>
Given that,
Rick jogged the same distance on tuesday and friday
Let "x" be the distance jooged on each tuesday and friday
He also jogged for 8 miles on sunday
Total of 20 miles for the week
Therefore, we frame a equation as,
total distance jogged = miles jogged on tuesday + miles jogged on friday + miles jogged on sunday
20 = x + x + 8
20 = 2x + 8
2x = 20 - 8
2x = 12
x = 6
Thus Ricky jogged 6 miles on tuesday and 6 miles on friday
Answer:
The socks are 40% off, and it is decreased to 60%.
Step-by-step explanation:
:))
