Answer:
The amount of money borrowed or invested is called as Principal. When you first take out a loan, the principal is the original amount you borrowed. As you pay toward that debt, the principal becomes the outstanding balance on the loan, not including interest and any fees accrued.
Step-by-step explanation:
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Answer:
33.33% probability that it takes Isabella more than 11 minutes to wait for the bus
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is given by the following formula.
For this problem, we have that:
Uniformly distributed between 3 minutes and 15 minutes:
So 
What is the probability that it takes Isabella more than 11 minutes to wait for the bus?
Either she has to wait 11 or less minutes for the bus, or she has to wait more than 11 minutes. The sum of these probabilities is 1. So
We want P(X > 11). So
33.33% probability that it takes Isabella more than 11 minutes to wait for the bus
Your answer should be 0.125<1/4<2.5%
0.125 being the least and 2.5% being the greatest
ΔRSP ≅ ΔQSP by SAS. Therefore, PR ≅ PQ by CPCTC theorem.
<h3>What is the CPCTC Theorem?</h3>
If two triangles are congruent, the CPCTC theorem states that all corresponding parts of the two triangles would also be congruent to each other.
Since S is the midpoint of QR, therefore, RS ≅ QS (one pair of congruent sides)
∠RSP ≅ ∠QSP [right angles] (one pair of congruent included angles)
SP ≅ SP based on the reflexive property (one pair of congruent sides)
Therefore, ΔRSP ≅ ΔQSP by SAS.
Conclusively, PR ≅ PQ by CPCTC theorem.
Learn more about the CPCTC theorem on:
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The pair of rational numbers with their sum are matched.
<h3 /><h3>What is rational number?</h3>
The numbers in the form of p/q is called the rational number.
1. -2/a²b +2/ab² = ( -2ab² +2a²b) / a³b³
= 2(a-b)/a²b²
2. 1/2ab -1/4a²b² =( 4a²b² -2ab) / 8a³b³
= 2ab -1 /4a²b²
3. 2/a²b³ -2/ab = (2ab -2a²b³) / a³b⁴
= 2( 1- ab²) /a²b³
4. 1/ab³ -1/a²b = a²b - ab³ / a³b⁴
= (a - b²) / a²b³
Thus, all the rational numbers are matched with their sum.
Learn more about rational numbers.
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