The interior angle of a regular polygon is equal to each other since all sides of the polygon are congruent. The formula that expresses the relation of the sides of the polygon and the measurement of the interior angle is (n2)*180/n where n is 7. Each interior angle then measures 128.6 degrees.

3 0

3 years ago

Does a heptogon have parallel lines please. help me

Tpy6a [65]

No they do not have parallel lines

4 0

3 years ago

In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2

drek231 [11]

Answer: ∠A=48°,∠B=48°,∠C=84°.

Step by-step explanation:

Given: AD and BE are the angle bisectors of ∠A and ∠B

i.e ∠6=∠7 ( ∵ Angles formed after AD bisected ∠A)

∠4=∠5 ( ∵ Angles formed after BE bisected ∠B)

Also, DE║AB

⇒ ∠2=∠7 (∵ Alternate interior angles)

∠3=∠6 (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x ..(1)

To Find: ∠A,∠B,∠C.

Solution: ∠2=∠7 (∵ Given) ...(2)

∠2=∠4 (∵ angles on the same segment) ...(3)

∠4=∠5 =∠B/2 (∵ Given) ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

⇒15x = 180°

⇒x=12°

Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, ∠B=∠A=48°

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

⇒∠C=84°

6 0

3 years ago