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Vesnalui [34]
4 years ago
11

Find the slope of the line passing through the points

Mathematics
2 answers:
yuradex [85]4 years ago
6 0

remember the slope is (y2-y1)/(x2-x) so the slope for this would be (5-(-6))/(-4-(-9)). when you solve that, it would become 11/-13. That is your slope.

Maru [420]4 years ago
3 0

Hope i helped!!! :)

Have a nice day :)


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Mrs. O'Neill had nine times as many markers as colored pencils the total number of markers and colored pencils is 110 how many c
tamaranim1 [39]

9x+x=110

10x=110

divide 10 on both sides

x=11

11 colored pencils

99 markers

5 0
4 years ago
In how many ways can 4 light bulbs be selected from a batch of 43 lights bulbs to be tested for defects? Assume no light bulb wi
lesantik [10]

Answer:

There are 123,410 ways

Step-by-step explanation:

The number of ways or combinations in which we can select k elements from a group of n elements is given by:

\frac{n!}{k!(n-k)!}

In this case, we can replace n by 43 and k by 4, because we are going to select 4 light bulbs from a batch of 43 light bulbs.

So, the number of combinations is calculated as:

\frac{43!}{4!(43-4)!}=123,140

It means that there 123,410 ways to select 4 light bulbs from a batch of 43 lights bulbs to be tested for defects

6 0
4 years ago
(16 points) (geometry) i need help plzzzzz
Rom4ik [11]

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Step-by-step explanation:

6 0
3 years ago
The equation 2/5d-1=3/5d-3 represents the number of dimes
ollegr [7]

Answer:

d=10

Step-by-step explanation: step 1: 2/5d-1 = 3/5d-3           add 3 to both sides

                                                                   +3          +3

                                            step 2:  2/5d+2 = 3/5d subtract 2/5d to both sides

                                                         -2/5d       -2/5d

                                            step 3:         2 =  1/5d       multiply 5/1 to both sides

                                                              * 5/1 = *5/1

                                                                10 = d

                                                 

8 0
3 years ago
Consider an unreliable communication channel that can successfully send a message with probability 1/2, or otherwise, the messag
Anon25 [30]

Answer:

6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Step-by-step explanation:

Consider the provided information.

Let x is the number of times massage received.

It is given that the probability of successfully is 1/2.

Thus p = 1/2 and q = 1/2

We want the number of times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once.

According to the binomial distribution:

P(X=x)=\frac{n!}{r!(n-r)!}p^rq^{n-r}

We want message is received at least once. This can be written as:

P(X\geq 1)=1-P(x=0)

The probability of at least once is given as 63/64 we need to find the number of times we need to send the massage.

\frac{63}{64}=1-\frac{n!}{0!(n-0)!}\frac{1}{2}^0\frac{1}{2}^{n-0}

\frac{63}{64}=1-\frac{n!}{n!}\frac{1}{2}^{n}

\frac{63}{64}=1-\frac{1}{2}^{n}

\frac{1}{2}^{n}=1-\frac{63}{64}

\frac{1}{2}^{n}=\frac{1}{64}

By comparing the value number we find that the value of n should be 6.

Hence, 6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

7 0
3 years ago
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