Question 1 of 5

Suppose you deposited $10 into your savings account each month, as indicated in the table. Your account pays 4%, compounded mont

Orlov [11]

I think its D. $1,800 because 10.4 multiplied by twelve is 124.8 and if you multiply that by 15 you get $1.872.

4 0

3 years ago

riding find the length of the hypotenuse of the right triangle use pencil and paper explain how you can interpret the Pythagorea

noname [10]

Solution

Question 1:

- Use of the area of squares to explain the Pythagoras theorem is given below

- The 3 squares given above have dimensions: a, b, and c.

- The areas of the squares are given by:

$\begin{gathered} \text{For square of length }a\to a^2 \\ \text{For square of length }b\to b^2 \\ \text{For square of length }c\to c^2 \end{gathered}$

- The Pythagoras theorem states that:

"The sum of the areas of the smaller squares add up to the area of the biggest square"

Thus, we have:

$c^2=a^2+b^2$

Question 2:

- We can apply the theorem as follows:

$\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\ \\ c=\sqrt[]{676} \\ c=26 \end{gathered}$

Thus, the value of c is 26

7 0

1 year ago

5 1/3 times x=2/3<br> What is x?

Alla [95]

I think the answer would be the 0.039.

7 0

3 years ago

Read 2 more answers

-4x - 84 = 2x + 24 <br> ??????

yarga [219]

Answer:

x= -54

Step-by-step explanation:

-4x - 84 = 2x + 24

-4x + 2x= 24 + 84

-2x= 108

x= 108 ÷ (-2)

x= -54

5 0

3 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago