Observe the given data distribution table carefully.
The 5th class interval is given as,
The upper limit (UL) and lower limit (LL) of this interval are,
Thus, the upper-class limit of this 5th class is 17.4.
12.38 less than the product of 37 and x
1 answer:
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The answer is: " 270 minutes " .
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→ There are "270 minutes" in "4 hours and 30 minutes" .
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Explanation:
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Method 1):
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Note: 60 minutes = 1 hour (exactly);
30 minutes = ? hr ? ;
→ (30 minutes) * (1 hr/ 60 minutes) ;
= (30/60) hr = (3/6) hr = (3÷3)/(6÷3) hr ;
= "
hr " ;
or; write as: " 0.5 hr " .
_________________________________________________________
So "4 hours & 30 minutes" = 4 hours + 0.5 hours = 4.5 hours.
→ 4.5 hours = ? minutes ;
The answer is: " 270 minutes" . 4.5 hours *
;
= (4.5 * 60) minutes = " 270 minutes " .
→ The answer is: " 270 minutes ".
___________________________________________________________
Method 2)
___________________________________________________________
"4 hours and 30 minutes" = <u> ? </u> minutes " .
___________________________________________________________
→ " 4 hours = <u> ? </u> minutes " ;
→ 4 hr . * = (4 * 60) minutes = 240 min. ;
→ There are " 240 minutes in 4 hours" .
→ To find the number of "minutes" in "4 hours and 30 minutes" ;
→ we takes the number of minutes in 4 hours—which is "240 minutes"—and add "30 minutes" to that number; as follows:
→ " 240 minutes + 30 minutes " ;
to get: " 270 minutes " .
_______________________________________________________
→ There are "270 minutes" in "4 hours and 30 minutes" .
_______________________________________________________
The answer is: " 270 minutes " .
_______________________________________________________
__________________________________________________________
→ There are "270 minutes" in "4 hours and 30 minutes" .
__________________________________________________________
Explanation:
__________________________________________________________
Method 1):
__________________________________________________________
Note: 60 minutes = 1 hour (exactly);
30 minutes = ? hr ? ;
→ (30 minutes) * (1 hr/ 60 minutes) ;
= (30/60) hr = (3/6) hr = (3÷3)/(6÷3) hr ;
= "
or; write as: " 0.5 hr " .
_________________________________________________________
So "4 hours & 30 minutes" = 4 hours + 0.5 hours = 4.5 hours.
→ 4.5 hours = ? minutes ;
The answer is: " 270 minutes" . 4.5 hours *
= (4.5 * 60) minutes = " 270 minutes " .
→ The answer is: " 270 minutes ".
___________________________________________________________
Method 2)
___________________________________________________________
"4 hours and 30 minutes" = <u> ? </u> minutes " .
___________________________________________________________
→ " 4 hours = <u> ? </u> minutes " ;
→ 4 hr . *
→ There are " 240 minutes in 4 hours" .
→ To find the number of "minutes" in "4 hours and 30 minutes" ;
→ we takes the number of minutes in 4 hours—which is "240 minutes"—and add "30 minutes" to that number; as follows:
→ " 240 minutes + 30 minutes " ;
to get: " 270 minutes " .
_______________________________________________________
→ There are "270 minutes" in "4 hours and 30 minutes" .
_______________________________________________________
The answer is: " 270 minutes " .
_______________________________________________________