(81^-0.25)^3 = ( 1 / (81^0.25) )^3
<span>81^.025 is the 4th root of 81 which is 3 </span>
<span>Therefor </span>
<span>( 1 / (81^0.25) )^3 = (1/3)^3 </span>
<span>(1/3)^3 = 1/27 <-----
Hope I Helped You!!! :-)
Have A Good Day!!!</span>
Answer:
C
Step-by-step explanation:
Using the trigonometric identity
csc x = 
Given
sinΘ = - 0.4, then
cscΘ = 
= - 2.5 → C
Take half of the coefficient of x: It is 3, and half that is 3/2.
Then <span>x^2+3x=6 becomes:
</span><span> x^2+3x + (3/2)^2 =6 + (3/2)^2, and
(x+3/2)^2 = 6 + 9/4
You were not asked to solve the equation, but why not do it for the practice?
</span>Solve (x+3/2)^2 = 6 + 9/4 for x. There will be 2 values.
First you multiply the numbers you do have to get the number your looking for 1/7•14=2 and 2divided by 1/7=14 so 2 would be your answer
The first option is
The second option is
So, neither of them is equivalent to 
