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garri49 [273]
3 years ago
7

What is 5/6 + 3/8 in the simplest form

Mathematics
2 answers:
quester [9]3 years ago
6 0
20/24 + 9/24 = 29/24      
1 5/24
zlopas [31]3 years ago
3 0
5/6 + 3/8

Convert to denominators of 24:

20/24 + 9/24

Add the numerators:

29/24

Convert to mixed number:

1 5/24
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Write the equation in point slope intercept form of the line that passes through (6,-11) and is parallel to the graph of y=-2/3x
Alina [70]

Answer:

y+11=-2/3(x-6)

Step-by-step explanation:

To find the parallel line, we would just plug in the numbers in the point-slope form from what we're given. We have y=-2/3x+12 and (6,-11).

Point-slope form:

y-y1=m(x-x1) → y+11=-2/3(x-6)

m represents the slope, which is -2/3 in this situation.

y1 represents the y coordinate, which is -11 in this situation. However, when we plug in negative numbers in a point-slope form, we would do the opposite of the negative number, which is to make it a positive in point-slope form.

x1 represents the x coordinate, which is 6 in this situation.

8 0
2 years ago
Find the value of x
Ahat [919]

recall that a circle has a total of 360°.

so that missing central angle is then 360° - 110° - 65° - 90°. Well, the arc's angle measurement is the same as the central angle they're in, so the x° is the same as 360° - 110° - 65° - 90°.

4 0
2 years ago
Which triangles are congruent by AAS?
netineya [11]
For two triangles to be congruent by AAS:
1- Two angles in the first triangle must be equal to two angles in the second triangle
2- A non included side in the first triangle is equal to a non included side in the second triangle

Now, let's check our options. We will find that:
For the two triangles UTV and ABC:
angle T = angle A
angle V = angle C
TU (non-included between angles T & V) = AB (non-included between angles A & C)

Therefore, we can conclude that:
Triangles ABC and UTV are congruent by AAS

8 0
2 years ago
Read 2 more answers
Find a such that the solution of y'' + y' − 2y = 0, y(0) = a, y' (0) = 1 tends to zero as t → +∞.
Kay [80]

Answer:

Step-by-step explanation:

y'' + y' − 2y = 0, y(0) = a, y' (0) = 1

Auxialary equation is

m^2+m-2=0\\m=-2,1

General solution is

y=Ae^{-2x} +Be^x

y(0) = A+B =a

y'(0) = -2Ae^{2x} +Be^x = -2A+B = 1

Eliminate B to get

3A =a-1

We know that y tends to 0 when x tends to infinity for any finite A

i.e. a should be a finite real number.

8 0
3 years ago
11,091 in expanded form
I am Lyosha [343]

Answer:

10000 + 1000 + 0 + 90 + 1

oof its asking for it to be 20 words longs or something like that oof thats why im typing this.

6 0
3 years ago
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