Answer:
<u>Use cross-multiplication to solve these</u>
- 1) 6/2 = 4/p ⇒ 6p = 4*2 ⇒ p = 8/6 ⇒ p = 4/3
- 2) 4/k = 8/2 ⇒ 8k = 2*4 ⇒ k = 8/8 ⇒ k = 1
- 3) n/4 = 8/7 ⇒ n = 4*8/7 ⇒ n = 32/7
- 4) 5/3 = x/4 ⇒ x = 4*5/3 ⇒ x = 20/3
Answer:
Three more than the quotient of nine and a number cubed, decreased by two; 3 + StartFraction 9 Over n cubed EndFraction minus 2
Step-by-step explanation:
Answer:
it is C. y=3/x
Step-by-step explanation:
Answer:
the answer you are looking for is -5<n<4
Answer:
Step-by-step explanation:
let a=Ann's amt., b=Betty's amt.
a=2b+9
b+2b+9=60
3b+9-9=60-9
3b=51
b=$17
a=34+9=$43
