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Inga [223]
2 years ago
14

The employee benefits manager of a medium size business would like to estimate the proportion of full-time employees who prefer

adopting plan A of three available health care plans in the coming annual enrollment period. A reliable frame of the company's employees and their tentative health care preferences are available. Using Excel, the manager chose a random sample of size 50 from the frame. There were 17 employees in the sample who preferred plan A. Construct a 99% confidence interval for the proportion of company employees who prefer plan A. Assume that the population consists of the preferences of all employees in the frame. The lower boundary is 0.172
Mathematics
2 answers:
enot [183]2 years ago
8 0

Answer:

it's a because I did this test

mezya [45]2 years ago
4 0
The answer for THISS
You might be interested in
X 0 2 10 20
prisoha [69]


Use two points from the graph to check if they are constant. In this case let’s use (0,50) & (2,58)

To find slope you have to do the following.

y2-y1 / x2-x1

Plug in the values, 58-50/2-0
This gives you 4.

When you use two other points, in this case (10,90) (20,130) you get a slope of 4.

This means the slope is 4.

We are trying to get an equation of y=mx+b.
We have slope already which is 4. So now we plug in y=4x + b

Now we need to find b. There is an equation to solve for b. Which is b=y1-m(x1)

But b is the y-intercept so there is already a B which is 50

So the table IS a linear equation and the equation is y=4x+50.
8 0
3 years ago
CHEGG The accompanying observations are precipitation values during March over a 30-year period in Minneapolis-St. Paul. 0.32, 0
Marina86 [1]

Answer:

Mean 1.580666667 1.769333333

Standard Deviation 0.890741799 1.123161779

Step-by-step explanation:

When we run the commands in the R software we get the graphs as follows.

The commands were

qqnorm(c(0.32,0.52,0.77,0.81,0.96,1.2,1.31,1.43,1.62,1.87,1.95,2.1,2.48,3,3.37))

and

qqnorm(c(0.47,0.59,0.81,0.9,1.18,1.2,1.35,1.51,1.74,1.89,2.05,2.2,2.81,3.09,4.75))

We can plot the graphs in any other plotting software .

The results would be same .

We see there's a slight difference between the two graphs.

One curve goes above ( Minneapolis) for  0.4 and the other ( for St Paul) is below 0.4

5 0
3 years ago
Simplify the expression below 6m^5+15m^2/3m^2
densk [106]

Answer:6m^5+5

Step-by-step explanation:

To simplify 6m^5+15m^2/3m^2

We get

6m^5+5

8 0
3 years ago
Which pairs of angles in the figure below are virtual angles? Check all that apply
Sav [38]
Can you provide a picture of the angles? Thanks <3
7 0
3 years ago
Find the area. The figure is not drawn to scale.
ELEN [110]

area of a triangle is 1/2 x base x height

 base = 19

 height = 3

19 *3 = 57

1/2 x 57 = 28.5 square ft.

3 0
3 years ago
Read 2 more answers
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