Well, this is absolute value, so as a mixed fraction you would have to times the denominator to the whole number, and then add the answer of that to the numerator (2 x 2 x 1). After that, you should get a whole number as an answer, but make it as a fraction. (put the whole number you got on top of the denominator before (2) to make it a fraction). Then, again, since it's absolute value, then it into a negative. Hope this helps and hope it not confusing!!
Answer:
Step-by-step explanation:
Yes what is the problemo! :>
Answer:
R=-12
Step-by-step explanation:
6(1 + 3R) = 2(10R - 9) -4R
Distribute 6 through the parentheses
6+18R=2(10R-9)-4R
Distribute 2 through the parentheses
6+18R=20R-18-4R
Collect like terms
6+18R=16R-18
Move the variable to the left-hand side and change its sign
6+18R-16R=-18
Move the constant to the right-hand side and change its sign
18R-16R=-18-6
Collect like terms
2R=-18-6
Calculate the difference
2R=-24
Divide both sides of the equation by 2
R=-12
if you'd make me brainliest that'd be great, if not its ok as well! I hope this helped!!!
Answer:
$8,240
Step-by-step explanation:
We are given that,
Principle amount in the savings account, P = $5,000.
Rate of interest, r = 5% = 0.05
Time period, t = 10
Also, the interest is compounded monthly, n = 12
As, we now that the value of the investment is given by 
Thus, we have,
Investment Value = 
i.e. Investment Value =
i.e. Investment Value = 
i.e. Investment Value = 
i.e. Investment Value = $8,240
Hence, the investment amount after 10 years is $8,240.
Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
