Answer:
40, 5 and 3
See explaination for the details
Explanation:
A)
Consider the data.
Assume D-cache is empty
An integer size =4bytes
The cache block size =4bytes
Therefore, the number of D-cache misses for reading the first 40 integers is,
= (40×4)/4
= 160/4
= 40
b)
Consider the data.
Assume D-cache is empty
An integer size =4bytes
The cache block size =32bytes
Therefore, the number of D-cache misses for reading the first 40 integers is,
= (40×4)/32
= 160/32
= 5
c)
Consider the data.
Assume D-cache is empty
An integer size =4bytes
The cache block size =64bytes
Therefore, the number of D-cache misses for reading the first 40 integers is,
= (40×4)/64
= 160/64
= 3
Answer:B
Explanation:Showing parts of a whole.
Answer:
It will be average (B2:C2)
as it will select all the data between B2 and C2
Ammunition documents which caries bullet, fuses extra should be numbered properly.
<u>Explanation:</u>
A document number or page number should be well organized and he or she coordinates with assistant trainers who have involved it.
Since it is a training event. The trainer has to have a checklist and make as fill with page number and make sure page numbers are strictly followed during the training session. If any page number is misplaced through the training session it will be embracing the situation for trainer and student or staff who get the training.
