Answer:
see explaination
Explanation:
class Larger<T extends Comparable<T>> {
public boolean larger(T[] arr, T item) {
if (arr == null || item == null)
throw new IllegalArgumentException();
for (int i = 0; i < arr.length; i++) {
if (item.compareTo(arr[i]) < 0) {
return false;
}
}
return true;
}
}
Hard disk Drive, random access memory, USB flash memory
Answer:
48 65 6c 6c 6f 20 6d 79 20 6e 61 6d 65 20 69 73 20 54 61 79 6c 6f 72 20 57 72 69 67 68 74
So here is the code in Python:
n = 0.00 #this is a float because there are some numbers that are decimals.
while n < 20: #n which is 0.00 and while it is lower than 20 if runs the code below
n = n + 1 #it will add 1 to n everything it runs the code.
k = n / 2 #it will divide whatever n is everytime by 2
print(str(n) + '/2: ') # it's printing the number it's on
print(k) # prints the answer for the n.
You can change n to add by any, make n any num instead of 0.00 and you can change the while condition from n < 20 to any other logical statement. If you want to get creative you can take 2 inputs for numbers and make one of them the starting number and other one is the ending number. Also make sure to make n a number lower than you starting point because if you set n as your starting point then it will skip it.
Answer:
Explanation:
In MATLAB, the following command:
Performs the element by elemet division of A and B. This comand is called Right-array division.
So, in your case, we could divide A by B element by element, only using fully-vectorised code (ie. no loops), with the following code:
![a = [2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 33 34 35 36 37 38 39 40];b = [1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 43 45 47 49 50 54 59 60];C = a./b](https://tex.z-dn.net/?f=a%20%3D%20%5B2%204%206%208%2010%2012%2014%2016%2018%2020%2022%2024%2026%2028%2030%2032%2033%2034%2035%2036%2037%2038%2039%2040%5D%3B%3C%2Fp%3E%3Cp%3Eb%20%3D%20%5B1%203%205%207%209%2011%2013%2015%2017%2019%2021%2023%2025%2027%2029%2031%2033%2043%2045%2047%2049%2050%2054%2059%2060%5D%3B%3C%2Fp%3E%3Cp%3EC%20%3D%20a.%2Fb)
;
C would be the element by element division of A and B, with no loops.
