3(-4y+5)-8(-2y-4) can be written in the form (ay+b) by following the following steps:

Mathematics

2 answers:

vlabodo [156]3 years ago

6 0

It looks like it was done correctly to me

Dominik [7]3 years ago

4 0

Answer:

Does the correct answer necessarily HAVE to be one of those three options? Because I'm looking at the steps and there seems to no mistakes at all. Forgive me if I'm mistaken though!

Step-by-step explanation:

You might be interested in

Solve the inequality |6x + 2| < 10 and graph its solution.

mars1129 [50]

This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3

Second part: when (6x + 2) is negative.

-(6x + 2) < 10   Divide both sides of inequality by -1 and change the sign.

(6x + 2) > -10
   6x + 2 > -10
   6x > -10 - 2
   6x > -12 Divide both sides by 6.
   x > -12/6
   x > -2.

Combined solution:   x < 4/3 and x > -2

-2 < x < 4/3.

Graph is a line on the number line between -2 and 4/3.

-2 and 4/3 are excluded from solution.

8 0

3 years ago

Which of the following equations best describes a square root function that is reflected across the x-axis and has a vertex of (

Minchanka [31]

Answer:

Step-by-step explanation:

Rather than picking, let's try to construct one from the description.

reflected over the x axis means - $\sqrt{x}$

the vertex is usually at (0,0), now how do we move a graph? or in other words translating it.

To move left and right you use $\sqrt{x-h}$ where if you subtract h you move right and if you add h you move left. we go from (0,0) to (-4,2). so 0 to -4 is 4 left, so that means we add 4.

To move up and down we use $\sqrt{x}+v$ Here if v is positive you move up and if v is negative you move down. going from (0,0) to (-4,2) it moves up 2