22 - 14 = 8
so i think j = 8
Answer:
4.987 in
Step-by-step explanation:
Volume of a cube= (where x= side)
x³
we know that
124=x³
∛124=x
x=4.986630952 which rounds to
4.987
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
Answer:
B. 2x – 1 = 13 and x = 7
Step-by-step explanation:
We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.
Option A.
2x -1 = 13 and x = 6
Using this value in the equation, we get:
2(6) -1 = 13
12 - 1 = 13
11 = 13, which is not true. Hence this option is not valid
Option B.
2x - 1 = 13 and x = 7
Using the value in the equation, we get:
2(7) - 1 =13
14 - 1 =13
13 = 13, which is true. Hence this option is valid.
Option C.
2x + 1 =13 and x = 7
Using the value in the equation, we get:
2(7) + 1 = 13
15 = 13, which is not true. So this option is not valid
Option D.
2x - 1 = 13 and x = 11
Using this value in the equation, we get:
2(11) - 1 = 13
21 = 13, which is not true. Hence this option is not valid.