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3 years ago

14

The surface area of a rectangular prism is 208 cm. Two of the dimensions are 2cm and 10 cm. Find the measure of the other dimens

ion.

1 answer:

kompoz [17]3 years ago

6 0

2 times 10 equals 20

208 divided by 20 equals 10.4

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3 years ago

The landscape artist who designed New York City’s

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The landscape artist who designed New York City’s Central Park believed that providing scenic settings accessible to all would not only benefit the public’s physical and mental health <u>and also foster a sense of democracy. </u> (Option D: but also foster a sense of democracy).

<h3>What is sentence correction?</h3>

Sentence correction or sentence improvement is a type of grammatical practice where a sentence is given with a word or a phrase that requires grammatical changes or improvement.

Now,

When 'not only' is used, 'but also' must come after it. When utilizing a correlative conjunction like "not only," "but also," the goal should be parallelism, meaning that the words that come after both sides of the conjunction should be from the same part of speech.
Here, using 'and' after 'not only...' distorts the structure of the sentence.

Hence, Option D is the right response, i.e., The landscape artist who designed New York City’s Central Park believed that providing scenic settings accessible to all would not only benefit the public’s physical and mental health <u>and also foster a sense of democracy. </u> (Option D: but also foster a sense of democracy).

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2 years ago

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3 years ago

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3 years ago

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

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4 years ago