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Dafna11 [192]
2 years ago
12

Help me outttt !!!!!!!

Mathematics
1 answer:
baherus [9]2 years ago
8 0

Answer:

its 3rd choice lol

Step-by-step explanation:

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Emma did some early holiday shopping for herself and found some items that totaled $212.94. She was thirifty enough to purchase
Viktor [21]

Answer:

Her total is now $170.54.

Step-by-step explanation:

You would do 20% of 212.94 which is 42.40 then subtract that from 212,94 to get the answer.

4 0
3 years ago
Read 2 more answers
Which answer goes in what box
marissa [1.9K]

Answer:

(2,6) and (-2,6) is in the second box

(8,-2) and (8,2) is in the first box

(-5,7) and (-5,-7) is in the first box

(-3,-3) and (3,-3) is in the second box

4 0
2 years ago
What is the value of n?
andrey2020 [161]

Answer:

N = 17

Step-by-step explanation:

In a parallelogram the opposite angles are congruent, hence

4n - 2 = 2n + 32 ( subtract 2n from both sides )

2n - 2 = 32 ( add 2 to both sides )

2n = 34 ( divide both sides by 2 )

n = 17

4 0
2 years ago
Show that 1n^ 3 + 2n + 3n ^2 is divisible by 2 and 3 for all positive integers n.
Dmitry_Shevchenko [17]

Prove:

Using mathemetical induction:

P(n) = n^{3}+2n+3n^{2}

for n=1

P(n)  = 1^{3}+2(1)+3(1)^{2} = 6

It is divisible by 2 and 3

Now, for n=k, n > 0

P(k) = k^{3}+2k+3k^{2}

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = (k+1)^{3}+2(k+1)+3(k+1)^{2}

P(k+1) = k^{3}+3k^{2}+3k+1+2k+2+3k^{2}+6k+3

P(k+1) = P(k)+3(k^{2}+3k+2)

Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

divisible by 2 and 3.

Hence, by mathematical induction, P(n) = n^{3}+2n+3n^{2} is divisible by 2 and 3 for all positive integer n.

3 0
3 years ago
How do i solve these questions? <br><br> can someone please tell me thanks :)
Vika [28.1K]
To find the area of this just add the units I believe which is 21
Hope this helps good luck. Not sure if this is 100% right my last year teacher was a sucky one
6 0
3 years ago
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