Answer:
-1215
Step-by-step explanation:
you muiltpy by -3 every time
Answer:
We conclude that have 96390 different schedules.
Step-by-step explanation:
We know that In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart, Brahms, and Schubert. If he is setting up a schedule of the 6 piano sonatas to be played, and he has 18 Mozart, 3 Brahms, and 21 Schubert piano sonatas.
We calculate how many different schedules are possible:
![C_2^{18}\cdot C_2^3\cdot C_2^{21}=\frac{18!}{2!(18-2)!}\cdot \frac{3!}{2!(3-2)!}\cdot \frac{21!}{2!(21-2)!}=96390](https://tex.z-dn.net/?f=C_2%5E%7B18%7D%5Ccdot%20C_2%5E3%5Ccdot%20C_2%5E%7B21%7D%3D%5Cfrac%7B18%21%7D%7B2%21%2818-2%29%21%7D%5Ccdot%20%5Cfrac%7B3%21%7D%7B2%21%283-2%29%21%7D%5Ccdot%20%5Cfrac%7B21%21%7D%7B2%21%2821-2%29%21%7D%3D96390)
We conclude that have 96390 different schedules.
Answer:
12
Step-by-step explanation:
8.3 / .7
Multiply each by 10 to get rid of the decimal
83/7
We know that 84/7 =12 so this is close to 12
Answer:
6.36%
Step-by-step explanation:
What we should do is calculate the mean value when we have all the data and then calculate the mean with the random samples, and calculate the error.
First, average of all data:
(22 + 17 + 19 + 21 + 20 + 19 + 24) / 7 = 20.29
Average for the random sample:
(17 + 19 + 21) / 3 = 19
% error = | sample - all / all | * 100
replacing the values:
% error = | (19 - 20.29) /20.29 | * 100
% error = 6.36%