Simplify the product. (2+ V6) (2-16)

Which statement is not true for the function notation of the volume of a cube, V(s) = s3?

Volgvan

<h3>Answer:</h3>

b. The side length of a cube is dependent on the volume.

<h3>Step-by-step explanation:</h3>

The function definition V(s) means the volume (V) is dependent upon the side length (s), not the other way around.

4 0

3 years ago

Please help!!! Express the area of the entire rectangle.

Mademuasel [1]

17x +x to the second power

4 0

3 years ago

Find the value of x so that the function has the given value.

nataly862011 [7]

For h(x) = -7x + 10, x =1

For r(x) = 4/5x+ 7 , x = -15

Step-by-step explanation:

in order to find the value of x on which the functions will have given values, we will put the functions equal to the given values

So,

h(x) = -7x + 10; h(x) = 3

$h(x) = -7x+10\\3 = -7x+10\\3-10 = -7x+10-10\\-7 = -7x$

Dividing both sides by -7

$\frac{-7x}{-7} = \frac{-7}{-7}\\x = 1$

r(x) = 4/5x+7; r(x) = -5

$r(x) = \frac{4}{5}x +7\\-5 = \frac{4}{5}x +7\\-5-7 = \frac{4}{5}x\\-12 = \frac{4}{5}x\\x = -12 * \frac{5}{4}\\x = -15$

Keywords: Functions

Learn more about functions at:

#LearnwithBrainly

3 0

3 years ago

Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

The satisfied table of the given function $y = log_{b} (x)$

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

Step-by-step explanation:

Explanation :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

i)

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

y = -3

ii)

put x = $\frac{1}{4}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{4} )$

$y = log_{2} (2^{-2} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

y = -2

iii)

put x = $\frac{1}{2}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{2} )$

$y = log_{2} (2^{-1} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

y = -1

iv)

put x = 1 given b > 1 so we can choose b = 2

$y = log_{2} (1 )$ = 0

y = 0

v)

put x = $2$ given b > 1 so we can choose b = 2

$y = log_{2} (2 )$

y = 1

Final answer:-

The satisfied table of the given function

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

8 0

3 years ago

Read 2 more answers

Find the range. 4, 7, 5, 5 ,4, 5, 5, 7, 3

ioda

This is quite easy, but anyway:

In order, they are

3, 4, 4, 5, 5, 5, 5, 7, 7

7 - 3 = 4

4 would be the range

3 0

3 years ago

Read 2 more answers