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alina1380 [7]
4 years ago
14

What is the simplest form of i^16 plus i^6 minus 2i^5 plus i^13?

Mathematics
1 answer:
BARSIC [14]4 years ago
6 0
\bf \textit{recall that}\qquad i^4=1\qquad i^3=-i\qquad i^2=-1\\\\
-------------------------------\\\\
i^{16}+i^6-2i^5+i^{13}\implies i^{4\cdot 4}~+~i^{4+2}~-~2i^{3+2}~+~i^{4+4+4+1}
\\\\\\
(i^4)^4~+~i^4\cdot i^2~-~2\cdot i^3\cdot i^2~+~i^4\cdot  i^4\cdot  i^4\cdot  i^1
\\\\\\
(1)^4+[1\cdot -1]-[2(-i)(-1)]+[(1)(1)(1)(i)]
\\\\\\
1-1-2i+i\implies -i
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Answer:

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ATQ

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