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stepan [7]
2 years ago
13

Order them from least to great

Mathematics
1 answer:
laiz [17]2 years ago
4 0

Answer:

-21/2 <-5/2 < - 2 < - 1.75 <-1 <1.75 <9/4

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-5/3-9/2x=3/2<br> Simplify as much as possible
Murljashka [212]
-5/3-9/2x=3/2
-10/6-9/2x=9/6
-9/2x=19/6
x=19/6÷-9/2
x=-19/6×2/9
x=-38/54 or -19/27. Hope it help!
8 0
3 years ago
Pls help ima give BRAINLIST and a like
Hoochie [10]

Answer:

the letter in the green box should be 3.

i believe the full equation should be y= -3/2 x+1

Step-by-step explanation:

the y side keeps decreasing by 1 1/2 which in improper fraction form is -3/2. the x side keeps increasing by 1.

7 0
3 years ago
What is 6/5 x 10 please help
inessss [21]

Answer:

12

Step-by-step explanation:

easy peasy

5 0
2 years ago
Read 2 more answers
When consumers apply for credit, their credit is rated using FICO (Fair, Isaac, and Company) scores. Credit ratings are given be
Flura [38]

Answer:

a) The 99% confidence interval would be given by (589.588;731.038)

b) If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

661 595 548 730 791 678 672 491 492 583 762 624 769 729 734 706

Part a

Compute the sample mean and sample standard deviation.  

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n}  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}  

=AVERAGE(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

On this case the average is \bar X= 660.313

=STDEV.S(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

The sample standard deviation obtained was s=95.898

Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =16<30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. The degrees of freedom are given by:

df=n-1=16-1=15

We can find the critical values in excel using the following formulas:

"=T.INV(0.005,15)" for t_{\alpha/2}=-2.95

"=T.INV(1-0.005,15)" for t_{1-\alpha/2}=2.95

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}  

And if we find the limits we got:

660.313- 2.95\frac{95.898}{\sqrt{16}}=589.588  

[tex]660.313+ 2.95\frac{95.898}{\sqrt{16}}=731.038/tex]  

So the 99% confidence interval would be given by (589.588;731.038)

Part b

If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

4 0
2 years ago
Simplify question question 18<br><br> ILL MARK BRAINLIST
Ksju [112]

Answer:

x^9y^3

Step-by-step explanation:

Step 1: Write expression

(\frac{x^{\frac{3}{4} }}{y^{\frac{-1}{4} }} )^{12}

Step 2: Simplify Parenthesis

(x^{\frac{3}{4} }}{y^{\frac{1}{4} }} )^{12}

Step 3: Exponent Exponents

(x^{\frac{36}{4} }}{y^{\frac{12}{4} }} )

Step 4: Simplify

(x^9 }}{y^3 )

4 0
3 years ago
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