Don’t know sorry I’m just trying not a good person
Answer:
The rods remain radioactive for thousands of years, so storage is a difficult problem.
Explanation:
Fuel rods represents the main element of the reactor core of a nuclear power plant.
They contain uranium-238 (U-238) enriched with uranium-235 (U-235), which is very unstable; when the nuclei of uranium absorb slow neutrons, they undergo nuclear fission, breaking apart and releasing huge amounts of energy.
In the process, several neutrons are released alongside with other products, and when they are slown down, they can be absorbed by other nuclei of uranium, further inducing more fissions.
The half-life of U-238 is 4.5 billion years, while the half-life of U-235 is approx. 700 million years: this means that the fuel rods remain highly radioactive for a very long time. Therefore, it is necessary to properly dispose them in a safe place where they do not represent a hazard. For instance, fuel rods: for example, they can be placed in sealed containers (built using concrete/steel to shield from the radiation) and buried underground.
Wedges are a type of inclined plane. As a wedge is forced into a space in an object, it exerts force to widen the space. .. so wedges is like a nail.
Negative. If it has more protons than electrons it is positive. It is has more electrons than protons it is negative.
Answer:
Final velocity of the first person is 3.43m/s and that of the second person is 0.0242m/s
Explanation:
Let the momentum of the first person, the ball second person be Ma, Mb and Mc.
From the principle of the conservation of momentum, sum of the momentum before collision is equal to the sum of the momentum after collision.
Ma1 + Mb1 = Ma2 + Mb2.
The ball and the first person are both moving together with a common velocity 3.45m/s.
Let the velocity of the first person be v1
Therefore
67.5×3.45+ 0.041×3.45= 67.5v1 + 0.041×34
233.02 = 1.39+ 67.5v1
67.5v1 = 233.02 - 1.39 = 231.61
v1 = 231.61 / 67.5
v1 = 3.43m/s
The second person and the ball move together with a common velocity after catching the ball.
For the second person and the ball let their final common velocity be v
Mb2 + Mc2 = Mb3 + Mc3
0.041 × 34 + 57.5 ×0 = (57.5 + 0.041)×v
57.541v = 1.39
v = 1.39 /57.541
v = 0.0242m/s
