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Flauer [41]
3 years ago
5

a 50- kg block of concrete is pulled upward (not sideways) with a force of 600 n =what is the acceleration

Physics
1 answer:
Arte-miy333 [17]3 years ago
6 0

The weight of the block is (mass x gravity) = (50kg x 9.8 m/s²) = 490 N

The NET vertical force on the block is (490N down) + (600N up) = 110N up.

Acceleration = (net force) / (mass)

Acceleration = (110N up) / (50 kg)

<em>Acceleration = 2.2 m/s² up</em>

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Answer:

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Explanation:

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So, we can solve for T from (1):

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Replacing (3) in (2):

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(\frac{mg}{cos(15^\circ)})sin(15^\circ)=\frac{kq^2}{r^2}(4)

According to pythagoras theorem, the distance of separation (r) of the spheres are given by:

sin(15^\circ)=\frac{\frac{r}{2}}{L}\\r=2Lsin(15^\circ)(5)

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mgtan(15^\circ)=\frac{kq^2}{(2Lsin(15^\circ))^2}\\q=\sqrt{\frac{mgtan(15^\circ)(2Lsin(15^\circ))^2}{k}}\\q=\sqrt{\frac{10*10^{-3}kg(9.8\frac{m}{s^2})tan(15^\circ)(2(0.22m)sin(15^\circ))^2}{8.98*10^{9}\frac{N\cdot m^2}{C^2}}}\\q=1.95*10^{-7}C

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