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soldier1979 [14.2K]
3 years ago
14

Lucas is planting grass on the shaded portions of the yard. What will be the total area covered by​ grass?

Mathematics
1 answer:
maxonik [38]3 years ago
8 0

Complete Question:

Lucas is planting grass on the shaded portions of the yard. What will be the total area of covered by grass? Fill in the missing.

Part A= 12 x ? = ? ft²

Part B= 0.5 x ? x 9 = ?ft²

Part C= 0.5 x 7 x ? = ?ft²

Total Area= ?ft²

Answer:

A = 108ft^2

B = 27ft^2

C = 24.5ft^2

Area = 159.50ft^2

Step-by-step explanation:

Given

See attachment

From the attachment;

Part A is a rectangle with dimension 9ft by 12ft

So,

A = 12ft * 9ft

A = 108ft^2

Part B is a triangle with dimension: height = 6 and base = 9

The height is calculated as:

Height = 12ft - 6ft = 6ft

And the base is:

Base = 18ft - 9ft = 9ft

So, the area is:

B = 0.5 * 6ft * 9ft

B = 27ft^2

Part C is a triangle with dimension: height = 7 and base = 7

So, the area is:

C = 0.5 * 7 * 7ft^2

C = 24.5ft^2

Total Area is:

Area = A + B + C

Area = 108ft^2 + 27ft^2 + 24.5ft^2

Area = 159.50ft^2

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Answer:

$690

Step-by-step explanation:

The amount she makes in a week=her weekly salary + the commission on sales.

Amount=330 + 7.5% of 4800.

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The she would make if she sold $4,800 of merchandise is $690.

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A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January
Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that p = 0.23

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084

P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735

P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343

P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225

P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439

P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109

P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

E(X) = np = 10*0.23 = 2.3

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33

The expected number is 2.3 and the standard deviation is 1.33.

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3 years ago
What's p-(8+m) over -1+p if m is 1 1/9 and p is 1 7/8 please help
djyliett [7]
(p-8-m)/(-1+p)=1 1/9;p=1 7/8
(p+1)/(p+8+m)=1 1/9;p=1 7/8
1/(8+m)=10/9;p=15/8
that's as far as it can be solved
8 0
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