The answer is A I believe but I might be wrong.
The volume of the space not filled by the sphere is the difference between the volume of a cube with edge length 6 inches and the volume of a sphere with radius 3 inches.
<h3><u>Cube</u></h3>
The volume of a cube of edge length s is
... V = s³
When the edge length is 6 in, the volume is
... V = (6 in)³ = 216 in³
<h3><u>Sphere</u></h3>
The volume of a sphere with radius r is
... V = (4/3)π·r³
When the radius is 3 in, the volume is
... V = (4/3)π·(3 in)³ = 36π in³
<h3><u>Space</u></h3>
Then the volume of the space between the cube and the sphere is
... Vcube - Vsphere = 216 in³ - 36π in³ ≈ 102.9 in³ . . . . corresponding to choice C
Y= x + 3
1. Find the gradient(slope)
1 - 7 / - 2 - 4
=1
2. Find the y. Intercept ( c )
Y = x + c
Replace by any of the two coordinates given (4 , 7 )
7 = 4 + c
C= 3
Equation => Y = x + 3
1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
Answer:
2
(
6
x^
3
−
30
x
^2
+
2
x
−
1
)
Step-by-step explanation:
