There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
If you cross mulitply the answer would be 13.3
Substitution doesn't work for this, but elimination does.
-6x-8y=-20 +6( x+6y=-6)
-6x-8y=-20 + 6x+36y=-36
-6x and 6x cancel each other, add -8 and 36 to get 28, and -20 and -36 to get -56.
28y=-56
divide by 28 on both sides.
Y= -2
Then substitute y into one of the equations.
x+6(-2)=-6
x-12=-6
x=6
The ordered pair is (6,-2).
Start at -4 and go to the right 6 times on the number line and you should end up with 2
Answer:
Step-by-step explanation:
Hello!
You have the information for two variables
X₁: Number of consumer purchases in France that were made with cash, in a sample of 120.
n₁= 120 consumer purchases
x₁= 48 cash purchases
p'₁= 48/120= 0.4
X₂: Number of consumer purchases in the US that were made with cash, in a sample of 55.
n₂= 55 consumer purchases
x₂= 24 cash purchases
p'₂= 24/55= 0.4364
You need to construct a 90% CI for the difference of proportions p₁-p₂
Using the central limit theorem you can approximate the distribution of both sample proportions p'₁ and p'₂ to normal, so the statistic to use to estimate the difference of proportions is an approximate standard normal:
[(p'₁-p'₂) ±
*
]
![Z_{0.95}= 1.648](https://tex.z-dn.net/?f=Z_%7B0.95%7D%3D%201.648)
[(0.4-0.4364)±1.648 *
]
[-0.1689;0.0961]
The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.
I hope this helps!