Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Multiply it out
x^2 + 4x -8x -32
Combine like terms
x^2 -4x - 32
2x-4=3-x +1
<span>Simplifying
2x + -4 = 3 + -1x + 1
Reorder the terms:
-4 + 2x = 3 + -1x + 1
Reorder the terms:
-4 + 2x = 3 + 1 + -1x
Combine like terms: 3 + 1 = 4
-4 + 2x = 4 + -1x
Solving
-4 + 2x = 4 + -1x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add 'x' to each side of the equation.
-4 + 2x + x = 4 + -1x + x
Combine like terms: 2x + x = 3x
-4 + 3x = 4 + -1x + x
Combine like terms: -1x + x = 0
-4 + 3x = 4 + 0
-4 + 3x = 4
Add '4' to each side of the equation.
-4 + 4 + 3x = 4 + 4
Combine like terms: -4 + 4 = 0
0 + 3x = 4 + 4
3x = 4 + 4
Combine like terms: 4 + 4 = 8
3x = 8
Divide each side by '3'.
x = 2.666666667
Simplifying
x = 2.666666667</span>
2. C
Slope = 40/8 = 5
Slope of graph c = 5/1 = 5
3. D
Slope = 9/3 = 3
Slope of graph d = 81/27 = 3
