Ask question

Ask question

All categories

2 years ago

13

What is the exact circumference of a circle with a radius of 12 inches?

1 answer:

Mamont248 [21]2 years ago

5 0

It’s 75.4 , I’m not sure abt those answers up there

You might be interested in

Question 1: 3/4n+16=2-1/8n. Show work plzz for all i need help due tomorrow!!!

Bezzdna [24]

1) Multiply everything by 8. It clears the fractions.
It gives you 6n + 128 =16 - n
You add the -n to the other side of the equation.
It gives you 7n + 128= 16
You then subtract 128 from 16.
It gives you 7n= -112
You divide everything by 7
It gives you n=-17

7 0

2 years ago

Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}$

⇒ $\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}$

⇒ $(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

⇒ $(x-2)(x-6) =0$ or, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

If, (x-2)(x-6) =0, then x=2 or x=6

If, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$ , then $x^{2} -5x-2=4$

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0

3 years ago

Help! Hurry!!! NO SPAM!!!!!!!! I will mark brainliest if you get it correct, and show your work. Determine whether f is an expon

borishaifa [10]

Answer:

Yes f is a function of x

Step-by-step explanation:

f(x) means fuctoin of x thats what it stands for.

and it has a constant ratio of 1/2. Hope this helps!!

mark me as brainliest

5 0

2 years ago

What is the degree of polynomial blow? x^6+3-2x^2+4x^7-4x

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

hello :

the degree of polynomial is : 7

7 0

3 years ago

Read 2 more answers

Right Answer to theese three questions please???

Scilla [17]

I hope this helps you

4 0

2 years ago