Answer:

Step-by-step explanation:
Given,
Principal ( P ) = $ 6000
Amount ( A ) = $ 14550
Time ( T ) = 10 years
Rate ( R ) = ?
<u>Finding </u><u>the </u><u>Interest</u>
The sum of principal and interest is called an amount.
From the definition,

plug the values
⇒
Swap the sides of the equation
⇒
Move 6000 to right hand side and change its sign
⇒
Subtract 6000 from 14550
⇒
Interest = $ 8550
<u>Finding </u><u>the </u><u>rate </u>

plug the values
⇒
Calculate
⇒
⇒
Hope I helped!
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Answer:
a. 1/10 or 10%
b. 1/2 or 50%
Step-by-step explanation:
Since the combination of machines 1, 2 and 3 produce 100% of the total output when added together, then the probability of choosing a bolt at random that is defective is: 5 + 2 + 3 = 10% out of 100% or 10/100, which is 1/10 or 10%.
If the bolt that is choosen at random is defective, than the probability that it came from machine 1 is 5/10 or 1/2 which is also 50%.
Answer:
-7
Step-by-step explanation:
7 - (-4)= 11
+
3(-6)= -18
=-7
Answer:
72°
Step-by-step explanation:
Given that the radius(r) of the circle is 10 units and the length of arc ABC is 16π
The length of arc ABC = 
Where θ is the central angle in degrees.
Since the length of arc ABC is 16π,

The angle in a circle = 360°, therefore:
Central angle for arc AB (θ) = 360 - Central angle for arc ABC = 360 - 288 = 72°
Therefore the arc measure of arc AB is 72°
Answer:
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92
The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.