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SIZIF [17.4K]
3 years ago
5

An observer, whose eyes are 1.98 m above the ground, is standing 39.2 m away from a tree. The ground is level, and the tree is g

rowing perpendicular to it. The observer's line of sight with the treetop makes an angle of 20.9° above the horizontal. How tall is the tree?

Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

The tree is 16.25 m tall.

Step-by-step explanation:

Attached is a diagram that better explains the problem.

From the diagram we see that the distance between the top of the tree and the line of sight of the observer is x.

To find the height of the tree, we need to first find x and then add it to the height of the observers line of sight from the ground.

Using SOHCAHTOA trigonometric function:

tan(20) = x/39.2

=> x = 39.2 * tan(20)

x = 39.2 * 0.364

x = 14.27m

Hence, the height of the tree is:

(14.27 + 1.98)m

16.25m

The tree is 16.25 m tall.

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Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
15)<br> Solve for X<br> X\42=6<br> A)<br> 7<br> B)<br> 252<br> C)<br> 260<br> D)<br> 332
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Answer:

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Step-by-step explanation:

x\42=6

x=6*42

x=252

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Answer:

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Step-by-step explanation:

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