4x= 124
divide both sides by 4 to get x by itself
4x/4= 124/4
Cross out 4 and 4, divide by 4 and then becomes 1*1*x= x
124/4
12/4= 3
4/4= 1
Answer: x= 31
Answer:
8
Step-by-step explanation:
=(7−(−1))2+(4−4)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
=(8)2+(0)2‾‾‾‾‾‾‾‾‾‾√
=64+0‾‾‾‾‾‾√
=6‾√4
=8
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Step-by-step explanation:
it's gonna either be B or D
So all you have to do to find out how much she had before is add up both value 12.50+34.25= 46.75$ (answer)
because y-12.50=34.25 so you would have to had the 12.5 to the other side to find the value of Y