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zalisa [80]
3 years ago
7

In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two

respondents were from the same​ household.) Among the​ respondents, answered​ "none," said​ "one," said​ "two," said​ "three," and responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.
​P(four or more cell ​phones)
​(Round to three decimal places as​ needed.)
Mathematics
1 answer:
Hatshy [7]3 years ago
3 0
Consider an event to be unlikely if its probability is less than or equal to 0.05.
204+287+376+137+130=1134

130/1134= .115


No​, because the probability of a respondent with four or more cell phones in use is greater than 0.05.
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3x+5y=-3 x-5y=-5 show your work
frez [133]
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Both equations have a 5y  term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.

3x + 5y = -3
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4x + 0y = -8

The y terms cancel out since one is positive and one is negative. Now we can solve for x.

4x = -8

\frac{4x}{(4)} = \frac{-8}{(4)}

x = -2

Now plug -2 in for x in one of the original equations to find y.

(-2) - 5y = -5

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Answer:  (why is it 5 points?) Thats ok.

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Step-by-step explanation:

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Kisachek [45]

Answer:

First blank: 4

Second blank: 3

Third blank: 8

Step-by-step explanation:

The expressions must be equivalent, yet one must read as 4 times the length of the box.

Looking at the given expression, 12x + 32, both numbers can be evenly divided by 4.

Since the blank spaces contain parenthesis, I can assume the problem is asking us to factor the numbers.

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