I cant see on my
computer sorry<span />
Answer:
Angle GHF ~ KHJ
Angle GFH ~ KJH
Angle FGH ~ JKH
Where side:
FH ~ JH
FG ~ JK
GH ~ KH
Step-by-step explanation:
True. A^2 + B^2 = C^2
A and B are the legs, C is the hypotenuse
The given problem is :
(6x^4 + 15x^3 − 2x^2 + 10x − 4) ÷ (3x^2 + 2)?
now we can write expression (6x^4 + 15x^3 − 2x^2 + 10x − 4) as
(6x^4 + 4x^2 + 15x^3 + 10x - 6x^2 -4)
we have somehow arrange the expression in a way that 3x^2 + 2 is common
now the expression comes out to be
2x^2(3x^2 + 2) + 5x(3x^2+2) -2(3x + 2) / (3x^2+2)
After dividing final result comes out to be (2x^2 + 5x -2)