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scoundrel [369]
2 years ago
13

A car is purchased for 1200. Each year it loses 25% of its value. After how many years will the car be worth 2800 or less?

Mathematics
1 answer:
Serga [27]2 years ago
8 0

Answer:

5.06 years

Step-by-step explanation:

It is already worth less than 2800

  perhaps you meant the purchase price was 12 000

2800 = 12 000 ( .75)^n

 n = 5.06 years   it will = 2800

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(T+10.5) + 2t + 90 = 180
Masja [62]

Answer:

x = 26.5

Step-by-step explanation:

Step 1: Write equation

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Step 2: Solve for <em>t</em>

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<u>Divide both sides by 3:</u> t = 26.5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

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5 0
4 years ago
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Solve for x. 3(3x - 1) + 2(3 - x) = 0 = 0
BARSIC [14]
If you would like to solve the equation 3 * (3 * x - 1) + 2 * (3 - x) = 0, you can calculate this using the following steps:

3 * (3 * x - 1) + 2 * (3 - x) = 0
3 * 3 * x - 3 * 1 + 2 * 3 - 2 * x = 0
9 * x - 3 + 6 - 2 * x = 0
7 * x + 3 = 0
7 * x = - 3    /7
x = - 3/7

The correct result would be - 3/7.
4 0
4 years ago
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