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3 years ago

14

What is the result of adding these two equations? 5x - y = 6 - 2x + y = 8

1 answer:

Eddi Din [679]3 years ago

5 0

Answer:

x=14/3

Step-by-step explanation:

5x-y=6

+ -2x+y=8

----------------

5x+(-2x)-y+y=6+8

5x-2x-y+y=6+8

3x=14

x=14/3

I apologize if something is incorrect, please me know how to fix it. Thank you!

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Help please someone I need all answers please

snow_tiger [21]

17. 8/10 is equal to .8 not .08
18a. False
18b. True
18c. False
18d. False
18e. True
19. 0.02
20. No, the zero needs to be in the tenths place or else the decimal (.2) would become 2/10.
21. 17/100
22. Words- Ten hundredths
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3 years ago

Writing g for the acceleration due to gravity, the period,T, of a pendulum of length l is given by

ivanzaharov [21]

Step-by-step explanation:

$T=2\pi\sqrt{\frac{l}{g}}$

$T+\Delta T=2\pi\sqrt{\frac{(l+\Delta l)}{g}} =2\pi\sqrt{\frac{l}{g}}\sqrt{1+\frac{\Delta l}{l}}=2\pi\sqrt{\frac{l}{g}}(1+\frac{1}{2}\frac{\Delta l}{l}+0(\frac{\Delta l}{l}))=T(1+\frac{1}{2}\frac{\Delta l}{l}+0(\frac{\Delta l}{l}))$

Here, the Taylor approximation for a square root was applied, and O(x) stands for all negligible terms of Taylor's sum with respect to variable x.

So, $\Delta T=T\frac{1}{2}\frac{\Delta l}{l}$

b. For an increase of 2%, that is:

$\frac{\Delta l}{l}=0.02$

$\frac{\Delta T}{T}=\frac{1}{2}0.02=0.01=1\%$

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3 years ago

Read 2 more answers

Which equation is true for the value a=7

andrey2020 [161]

Answer:

The answer is just re look at the question A

3 0

3 years ago

MAY SOMEONE PLZ HELP ME ON THIS, I DONT KNOW THE EQACTION

just olya [345]

Answer:

I will use "complete-the-square" approach if thats ok

first 0.5(x - 2)² - 2

second -2(x - 4)² + 8

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2 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

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3 years ago