Answer:
A system of two equations can be classified as follows: If the slopes are the same but the y-intercepts are different, the system has no solution. If the slopes are different, the system has one solution. If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.
Answer:
x=2y+8
y=
x-4
Step-by-step explanation:
Answer:
{3, 4}
Step-by-step explanation:
"M(x)=(2x-6)(x-4) true statements when M(x)=0 when x= ?" asks us to find the "roots" of M(x); that is, the x values at which M(x) = 0. Thus, we set
(2x - 6)(x - 4) = 0, which is equivalent to 2(x - 3)(x - 4) = 0.
Thus, x - 3 = and x = 3; also x - 4 = 0, so that x = 4.
The roots of M(x) are {3, 4}
Using the language of the original problem: "true statements when M(x)=0 when x=" the correct results, inserted into the blanks, are x = 3 and x = 4.
The perimeter would be 112. That’s the answer because after you multiply 6 and 8, you’ll get 48. But you can’t forget ℎ, ℎ and . In this case is 6. So you have to plug in;
ℎ: L= 8
ℎ: N•L = 6•8 = 48
So the perimeter is;
8 + 48 + 8 + 48 = 112
