Answer:
For this case we have this function given:

In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

And we can write this in formal notation as:
![D = [ X \in R | X>0]](https://tex.z-dn.net/?f=%20D%20%3D%20%5B%20X%20%5Cin%20R%20%7C%20X%3E0%5D)
And the best answer for this case would be:
all real numbers greater than 0
Step-by-step explanation:
For this case we have this function given:

In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

And we can write this in formal notation as:
![D = [ X \in R | X>0]](https://tex.z-dn.net/?f=%20D%20%3D%20%5B%20X%20%5Cin%20R%20%7C%20X%3E0%5D)
And the best answer for this case would be:
all real numbers greater than 0
Short answer There are
2 places where the graph touches the x axis just as you said.
I take this to mean f(x) = (x - 6)^2*(x + 2)^2
There are two places where the graph touches the x axis but that is not an intercept.
When a graph just touches the x axis, that counts as a root. As the graph shows, these 2 places are
x = 6 and
x = - 2 is where they touch.
If you have a graphing calculator, you can see what this looks like for yourself. The window settings are
x min = - 3
x max = 7
y min = 0
y max = 250.
There is a local maximum between x = -2 and x = 6.
So the answer, once again is at x = -2 and x = 6 and that makes 2 roots for the equation.
Yes. <span>You can solve a system of equations through addition, subtraction, multiplication, or substitution.</span>
Answer:
Step-by-step explanation:
9) 24=6(-x-3)
24=-6x-18
42=-6x
x=-7
10) 75=3(-6n-5)
75=-18n-15
90=-18n
n=-5
11) -3(1+6r)=14-r
-3-18r=14-r
17=-17r
r=-1
12) 6(6v+6)-5=1+6v
36v+36-5=1+6v
36v+31=1+6v
30=-30v
v=-1
13) -4k+2(5k-6)=-3k-39
-4k+10k-12=-3k-39
6k-12=-3k-39
9k=-27
k=-3
14) -16+5n=-7(-6+8n)+3
-16+5n=42-56n+3
-16+5n=45-56n
61=-61n
n=-1
plz mark brainliest