Select all of the names? Z

Mathematics

1 answer:

Nataly_w [17]3 years ago

5 0

Answer:

2 y 4

Step-by-step explanation:

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|x-2| + |2x+1| ≥ 3<br> How to solve this inequality? HELP

Phoenix [80]

Answer: $\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0\:\\ \:\mathrm{Decimal:}&\:x\le \:-0.66666\dots \quad \mathrm{or}\quad \:x\ge \:0\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{2}{3}]\cup \:[0,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

$\left|x-2\right|+\left|2x+1\right|\ge \:3$

$x$

$x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:0\le \:x$

$x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0$

4 0

3 years ago

I need help... the question is confusing

ziro4ka [17]

$\bf \stackrel{line~J}{y+8=-(x-2)}\implies y+8=-x+2
\\\\\\
y=-x-6\implies y=\stackrel{slope}{-1}x-6$

now we know the slope of line J is -1.

a line perpendicular to J, will have a negative reciprocal slope, therefore,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -1\implies \cfrac{-1}{\underline{1}}\\\\
negative\implies +\cfrac{1}{{{ \underline{1}}}}\qquad reciprocal\implies + \cfrac{{{ \underline{1}}}}{1}\implies 1$

therefore, line K has a slope of 1, and passes through 3,4,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
% (a,b)
&&(~{{ 3}} &,&{{ 4}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 1
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-4=1(x-3)\implies y-4=x-3
\\\\\\
y=x+1$

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3 years ago

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3 years ago

If f(x)=2x-7, then find f(8)

Artyom0805 [142]

It should be 9. I hope this helps. If it's not 9 then can u please give me a list of your answers to choose from.

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ycow [4]

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Step-by-step explanation:

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