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Ronch [10]
3 years ago
6

John has a roll containing 24 2/3 feet of wrapping paper. he wants to divided it into 11 pieces, first though he must cut off 5/

6 foot because it is torn. How long will each piece be?
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0

Answer:

2\frac{1}{6} foot

Step-by-step explanation:

John has a roll containing  24\frac{2}{3} feet of wrapping paper.

He must cut off  \frac{5}{6} feet.

Now the left over wrapping paper =  24\frac{2}{3} -  \frac{5}{6}

                                                      =  \frac{74}{3} -  \frac{5}{6}

                                                      =  \frac{148-5}{6}

                                                      =  \frac{143}{6}

                                                      =  23\frac{5}{6}

He wants to divide the left over wrapping paper into 11 pieces.

23\frac{5}{6} ÷ 11

\frac{143}{6} ÷ 11

\frac{143}{6} ×  \frac{1}{11}

\frac{143}{66}

\frac{13}{6}

2\frac{1}{6} foot

Each piece would be  2\frac{1}{6} foot long.

Nadusha1986 [10]3 years ago
4 0

Ok, so first you have to take the 5/6th off. This would be 24 4/6 - 5/6th which would be 23 and 5/6ths. The next step would be to turn the 5/6 into a decimal. That would be 0.83333 so 23.83 divided by 11.  The answer would be 2.166363664 according the the calculator. HOPE THIS HELPS!!!

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