<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer: The inequality solves to x ≥ 42
The graph is shown below
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Explanation:
We have some unknown number x, and we're dividing by 6 to form the fraction x/6. That result is 7 or larger which means we write x/6 ≥ 7
To solve for x, we undo the division. We'll multiply both sides by 6. That's how we get to x ≥ 42
The graph will involve a number line. Plot a closed filled in circle at 42 on the number line. Shade to the right. This visually represents any number that is 42 or larger. The endpoint 42 itself is included in the solution set.
Side note: We would use an open circle if we didn't have the "or equal to" portion for the inequality sign.
9514 1404 393
Answer:
x = -(9/7)n -81
Step-by-step explanation:
Subtract the n term.
x/-9 = 9 -n/-7
Multiply by -9.
x = -81 -(9/7)n
Insert a picture so I can help you out :)
