The y-intercept of the linear function y = 3x - 2 is -2
<h3>How to determine the y-intercept?</h3>
The function is given as
y = 3x - 2
The above function is a linear function, and the y-intercept is the point on the graph, where x = 0 i.e. the point (0, y)
As a general rule, linear functions are those functions that have constant rates or slopes
Next, we set x to 0, and calculate y to determine the value of the y-intercept
y = 3(0) - 2
Remove the bracket in the above equation
y = 3 * 0 - 2
Evaluate the product of 3 and 0 i.e. multiply 3 and 0
y = 0 - 2
Evaluate the difference of 0 and -2 i.e. subtract 0 from 2
y = -2
The above means that the value of y when x is 0 is -2
Hence, the y-intercept of the linear function y = 3x - 2 is -2
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The answer to your problem is -9 and 3/4.
The scale factor is 3 because the units of segments are given equally to us.
<u>Given</u><u> </u><u>:</u>
<u>To</u><u> </u><u>Find</u><u> </u><u>:</u>
<u>Answer</u><u> </u><u>:</u>
- x + y = 4 ....[Equation (i)]
- x + y = 1......[Equation (ii)]
<u>Adding</u><u> </u><u>eqⁿ (ii) </u><u>and</u><u> eqⁿ (i) we get :</u>
→ x + y + x - y = 4 + 1
→ 2x = 5
→ x = 5/2
→ x = 2.5
<u>Now</u><u>,</u><u> </u><u>put</u><u> </u><u>the</u><u> </u><u>value </u><u>of</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>5</u><u>/</u><u>2</u><u> </u><u>in</u><u> </u><u>eqⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>we</u><u> </u><u>get</u><u> </u><u>:</u>
→ x + y = 4
→ 5/2 + y = 4
→ y = 4 - 5/2
→ y = 1.5