Answer:
80 feet
Step-by-step explanation:
length of pool = 22 , width of pool = 18
feet required for fencing the pool = 2 (l +b)
= 2 ( 22+18)
=2*40
=80feet
Y/22 would be the answer to your question.
Let's find the value of x
Since the sum of internal angles of a triangle is 180°
therefore,
![\hookrightarrow \: (2x - 2) \degree + (x + 5) \degree + 90 \degree = 180 \degree](https://tex.z-dn.net/?f=%20%20%5Chookrightarrow%20%5C%3A%20%282x%20-%202%29%20%5Cdegree%20%2B%20%28x%20%2B%205%29%20%5Cdegree%20%2B%2090%20%5Cdegree%20%3D%20180%20%5Cdegree)
![\hookrightarrow \: 2x - 2 \degree + x + 5\degree = 180\degree - 90\degree](https://tex.z-dn.net/?f=%20%5Chookrightarrow%20%5C%3A%202x%20-%202%20%5Cdegree%20%2B%20x%20%2B%205%5Cdegree%20%20%3D%20180%5Cdegree%20-%2090%5Cdegree)
![\hookrightarrow \: 3x + 3\degree = 90\degree](https://tex.z-dn.net/?f=%20%5Chookrightarrow%20%5C%3A%203x%20%2B%203%5Cdegree%20%3D%2090%5Cdegree)
![\hookrightarrow \: 3(x + 1) = 3(30)](https://tex.z-dn.net/?f=%20%5Chookrightarrow%20%5C%3A%203%28x%20%2B%201%29%20%3D%203%2830%29)
![\hookrightarrow \: x + 1\degree = 30\degree](https://tex.z-dn.net/?f=%20%5Chookrightarrow%20%5C%3A%20x%20%2B%201%5Cdegree%20%3D%2030%5Cdegree)
![\hookrightarrow \: x = 29\degree](https://tex.z-dn.net/?f=%20%5Chookrightarrow%20%5C%3A%20x%20%3D%2029%5Cdegree)