![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
I think it’s the first and fourth
Step-by-step explanation:
Hope this helps!!!!
9,000 that will be you answer or if is double will be 18,000
Answer: There are no solution
Step 1: Simplify both sides of the equation.
3(x+5)−3=2(3x+1)−3x
(3)(x)+(3)(5)+−3=(2)(3x)+(2)(1)+−3x(Distribute)
3x+15+−3=6x+2+−3x
(3x)+(15+−3)=(6x+−3x)+(2)(Combine Like Terms)
3x+12=3x+2
3x+12=3x+2
Step 2: Subtract 3x from both sides.
3x+12−3x=3x+2−3x
12=2
Step 3: Subtract 12 from both sides.
12−12=2−12
0=−10
Answer:
5
Step-by-step explanation:
Add each number up and then divide by how many numbers there are in this set (5)
2+4+5+6+8=25
25/5=5
