The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
207 cm
Step-by-step explanation:
Because ΔPQR ≅ΔSTU and the longest side in the ΔPQR is RP then the longest side in ΔSTU must be SU = 92 cm
Perimeter of triangle PQR is
P(ΔPQR) = 36+48+24 = 108 cm
Because the triangles are are similar their sides are in proportion.
But how much bigger did the second triangle get?...is (92/48) times bigger
P(ΔSTU) = 180*(92/48) = 207 cm
...you can also use proportions to find each side and then find the perimeter
TU = 24*92 /48 = 46
TS = 36*92/48 = 69
SU = 92
P(ΔSTU) = 92+69+46 =207 cm
*the triangles are not drawn to scale