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Sauron [17]
3 years ago
14

(PLEASE HELP/NO SPAM) Which equation shows the function y=2^x translated 4 units left and 2 units down?

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

The answer is (h).

Step-by-step explanation:

When y = 2^x is shifted 4 units left, the x shifts 4 units to the left and x becomes (x+4). When the graph is shifted to units down, y has to be subtracted by 2.

The function becomes

y = 2^(x+4) -2.

Finally, you shift -2 to the same side as y.

This becomes

y+2 = 2^(x+4) which is (h)

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kari74 [83]

So we need to convert 0.75 feet to inches.

0.75 feet = 9 inches

Then we divide 9 by how many hours are in a day: 24

9/24 = 0.375

The raindrop vine can grow up to 0.375 inches per hour.


6 0
3 years ago
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I don't under stand what is wrong.
MAXImum [283]

Answer:

In the first step, there is an issue when distributing the -3 to the terms inside of the parentheses. When multiplying the -3 to the -5, you would get an answer of +15, not -15.

The full correct process is:

(4m + 9) - 3(2m - 5) = 4m + 9 - 6m + 15

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                                = -2m + 24

4 0
2 years ago
Which of the following would best represent a cosine function with an amplitude of 3, a period of pi/2 , and a midline at y = –4
Grace [21]
To transform the function f(x)= cos(x) to have the amplitude of 3, we need to multiply the constant 3 to the function f(x), so we have y=3f(x)

To transform the function f(x)=cos(x) to have the midline y=-4 we need to subtract f(x) by 4, so we have y=f(x)-4, 

To transform the function f(x)=cos(x) to have period of \frac{ \pi }{2}, we need to divide the original period 2 \pi by 4, so we have y=f(4x). Note that it is the 4x gives the effect of dividing the points on x-axes by 4 and the period is read on x-axes

Hence, the full transformation is given y=3f(4x)-4 which is the last option
8 0
3 years ago
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Alik [6]

Answer:

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To get percentage from a decimal, move the decimal point to the right two place values

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4 0
3 years ago
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Graph y > x^2 - 5. Click on the graph until the correct one appears.
kenny6666 [7]

y=x^2\\\\for\ x=\pm2\to y=(\pm2)^2=4\to(-2;\ 4);\ (2;\ 4)\\\\for\ x=\pm1\to y=(\pm1)^2=1\to (-1;\ 1);\ (1;\ 1)\\\\for\ x=0\to y=0^2=0\to (0;\ 0)

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y > x^2-5 /look at the picture #2/ - your answer

7 0
3 years ago
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