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gladu [14]
3 years ago
14

What is the area of a square whose diagonal is 4? A. 8 B.32 C.36 D.64

Mathematics
2 answers:
Oksana_A [137]3 years ago
5 0
I think the answer is 8
andrezito [222]3 years ago
5 0

Answer:

A

Step-by-step explanation:

you need to use a formula solving for A

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Sort the following numbers from least to greatest.<br> 18.5635, 18 13/16, 18.3125
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18.3125

18.5635

18 13/16

Step-by-step explanation:

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3 years ago
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If f(x)=x and g(x)=2, what is (f o g)(x)?
IgorC [24]

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Step-by-step explanation:

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Which is the graph of the step function f(x)? f(x) = StartLayout Enlarged left-brace 1st row 1st column negative 1 2nd column x
Andrews [41]

Answer:

its B

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5 0
3 years ago
Let a=x^2+4. Use a to find the solutions for the following equation:
Helga [31]
(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4 
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>

<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>

<span>x = -2, 0, +2 so your answer is going to be e

</span>
4 0
3 years ago
Read 2 more answers
  What values for θ (0 ≤ θ ≤ 2pie ) satisfy the equation? 
svetoff [14.1K]
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
7 0
3 years ago
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