1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slavikrds [6]
2 years ago
12

Someone please help me with these or at least tell me how it works

Mathematics
1 answer:
Katarina [22]2 years ago
5 0
Alright! So the easiest way for me personally is to make the fraction over a number like 10 or a 100. So... for 5/20, I would multiply both numbers by 5. That gives you 25/100.

Then you could just divide.

Hope that makes sense! Let me know if you any more help!!
You might be interested in
Answer. it fast please​
mojhsa [17]

Answer:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

Step-by-step explanation:

Given

(\frac{6}{10})^3 * (\frac{5}{9})^2

Required

Solve:

(\frac{6}{10})^3 * (\frac{5}{9})^2

Simplify 6/10

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2

Express 9 as 3^2

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2

Apply law of indices

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}

Express as a sing;e fraction

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}

Apply law of indices:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

5 0
2 years ago
a collection of coins consist of nickels, dimes, and quarters. there are 3 fewer quarters than nickels and six more dimes than q
ZanzabumX [31]
There are 12 Nickels, 9 Quarters, and 15 Dimes.
7 0
3 years ago
Solve 15 ≥ -3x or x ≥ -2.
vivado [14]

Answer:

x ≥ - 2.

Step-by-step explanation:

We have to solve the compound inequality.

It is 15 ≥ - 3x or x ≥ - 2

Now, from the first part we have  

15 ≥ -3x

⇒ -\frac{1}{3} \times 15 \leq  -\frac{1}{3}(- 3x)

⇒ - 5 ≤ x

⇒ x ≥ - 5 ....... (1)

And the second part is x ≥ -2 ......... (2)

Therefore, the conditions (1) and (2) will both be true if x ≥ - 2.

Hence, this is the solution. (Answer)

4 0
3 years ago
Which is the last sentence of the proof? because f + e = 1, a2 + b2 = c2. Because f + e = c, a2 + b2 = c2. Because a2 + b2 = c2,
lyudmila [28]

The latest sentence of proof by using the triangle congruence method we can conclude that f+e=c, a^{2} + b^{2} = c^{2}.

Given that ΔABC and ΔCBD are right triangles

Therefore, one angle of both triangle is of 90°

So, ∠B is same in both triangles. Hence, by suing the Angle-Angle theorem rule we can conclude that both ΔABC and ΔCBD are similar.

Consequently, ∠A is same in both triangles. Hence, by suing the Angle-Angle theorem rule we can conclude that both ΔABC and ΔCBD are similar.

Similarly, When two triangles are similar then their corresponding angles are equal and their corresponding sides are also equal.

Therefore , the two proportions can be rewritten as

a² = cf ( equation 1 )

b² = ce ( equation 2 )

By adding b² on both side of equation 1 then we can write equation 1 as

a^{2} + b^{2} = b^{2}+cf

a^{2} + b^{2} = ce+cf

Because b² and ce are equal and substitute on the right side of equation 1

Using the converse of distributive property  in above equation then we get a new equation. That is,

a^{2} +b^{2}  = c(f+e)

Because distributive property is a(b+c)=a(b+ac)

a² + b² = c²

Because e + f = c²

To learn more about triangle congruency: brainly.com/question/1675117

#SPJ4

6 0
11 months ago
How to get the answer
Aleonysh [2.5K]
So this is just working with exponents, but negative exponents can be a little tricky. your example didn't do a great job of showing how you calculate negative exponents.

for #2, you have 10⁻⁶

to convert negative exponents into something that makes more sense to our brain, you can set it beneath 1:

\frac{1}{10^6}  ... or, in the event that you can't see that because you're on the app: (1)/(10⁶). so now, instead of calculating 10⁻⁶, which would probably give you a confusing decimal, you just need to figure out 10⁶ -- and positive exponents are much easier to deal with.

10⁶ = 1,000,000
BUT remember that you have to put this value beneath a 1 to account for your negative exponent and (1/1,000,000) is your answer for part A.

so, use the same steps for the rest of the problems:
1) convert negative exponent to positive exponent beneath 1
7⁻³ = (1)/(7³)
2) calculate 7³
7³ = 343
<span>3) your result is (1/343)
</span>
<span>for 12</span>⁻², again, you'll put it beneath 1 so that it becomes (1)/(12²), then you'll calculate 12² (12*12 = 144), so that your result is (1/144). that leaves the letter D for number 2, which you'll have to write into your boxes at the top.

i hope this helps! you can message me if you have any specific ones that cause you trouble and i'll do my best to help.
5 0
3 years ago
Other questions:
  • What are three rational numbers between 0.2 and 0.3 (one must be a fraction)?
    6·2 answers
  • Of the town's 42 firefighters, 16 volunteered for the special rescue team. Express the portion who did not volunteer.
    13·1 answer
  • Convert 2 5/6 to an improper fraction
    10·1 answer
  • 6x – 6y = 0<br> 3x + y =- 12
    12·1 answer
  • −1.75 − 22/20<br> plz hlep<br> ...and put as an exact decimal or simplified fraction
    8·2 answers
  • Solve the inequality for x: 25 - 14x &lt; 53*
    13·1 answer
  • In a sample of 45 mice, a biologist found that 18 were able to run a maze in 30 seconds or less. Find the limits for the 95% con
    11·1 answer
  • 2x. 4<br> Find the measure of the<br> exterior angle shown.<br> 75°<br> (13x - 1990
    6·1 answer
  • Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to
    10·1 answer
  • Divide.<br><br> 7 9/6 divided by 2 3/4
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!