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2 years ago

Someone please help me with these or at least tell me how it works

Mathematics

1 answer:

Katarina [22]2 years ago

5 0

Alright! So the easiest way for me personally is to make the fraction over a number like 10 or a 100. So... for 5/20, I would multiply both numbers by 5. That gives you 25/100.

Then you could just divide.

Hope that makes sense! Let me know if you any more help!!

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3x2 - 2x = 0<br> Factorise and solve

malfutka [58]

Solve : 3x-2 = 0

Add 2 to both sides of the equation :

3x = 2

Divide both sides of the equation by 3:

x = 2/3 = 0.667

Two solutions were found :

x = 2/3 = 0.667

x = 0

hope this helped

6 0

2 years ago

Read 2 more answers

Solve for r 5(r-10)= -51

Sloan [31]

Answer:

r= -1/5

Step-by-step explanation:

Step 1: Remove the parentheses (5r-10= -51)

Step 2: Move the constant to the right-hand side and change the sign (5r= -51 + 50)

Step 3: Calculate the sum of -51 +50 (5r = -1)

Last Step: Divide both sides by the equation by 5 (r = -1/5)

4 0

2 years ago

What is the percent 5.89966

Lorico [155]

The answer is 5.9% I think because you have to round up if it’s 5 and above

4 0

3 years ago

Read 2 more answers

$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e

ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = $p_1$ = $A

And The money invested at 6% = $p_2$ = $13957 - $A

Let The interest earn at 7% = $I_1$

And The interest earn at 6% = $I_2$

$I_1$ - $I_2$ = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, $I_1$ = $\dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}$

Or, $I_1$ = $\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}$

And

$I_2$ = $\dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}$

Or, $I_2$ = $\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}$

∵ $I_1$ - $I_2$ = $833.73

So, $\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}$ - $\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}$ = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = $\dfrac{167115}{13}$

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102 . Answer

8 0

3 years ago

Can someone help me with this?

zvonat [6]

Sorry, don't have time to do them right now but I know who does!

http://www.wolframalpha.com/widgets/view.jsp?id=ae438682ce61743f90d4693c497621b7

Just plug in 2 at a time.

4 0

2 years ago