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hammer [34]
3 years ago
15

Please give the correct answer and I will give a brainless

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

It’s 40 I’m pretty sure because of the square. That’s how I was taught.

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2 2/3

hope i helped. (:

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3 years ago
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PLeAsE HeLp Someone​
liq [111]

Answer:

yes

Step-by-step explanation:

the answer its 5

5 0
3 years ago
2 At Bea's Pet Shop, the number of dogs, d, is initially five less than twice the number of cats, c. If she decides to add three
forsale [732]

Let D be dogs and C be cats

<em>dogs, d, is initially five less than twice the number of cats, c</em>

D + 5 = 2C

<em>If she decides to add three more of each, the ratio  of cats to dogs will be</em>

D + 8 = 2C + 3

<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>

Simply plug in the numbers

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This is clearly not true: 25 does not equal 30

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7 0
3 years ago
Please help!
mina [271]

Answer: A

Step-by-step explanation:

See how many times the coordinates are plot

7 0
3 years ago
Need help badly don’t have answer to this problem.
NikAS [45]
There are a couple of ways to tackle this one, using the 45-45-90 rule or just using the pythagorean theore, let's use the pythagorean theorem.

the angle at A is 45°, and its opposite side is BC, the angle at C is 45° as well, and its opposite side is AB, well, the angles are the same, thus BC = AB.

hmmm le'ts call hmmm ohh hmmm say z, thus BC = AB = z.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2 \implies (6\sqrt{2})^2=z^2+z^2&#10;\qquad &#10;\begin{cases}&#10;c=\stackrel{6\sqrt{2}}{hypotenuse}\\&#10;a=\stackrel{z}{adjacent}\\&#10;b=\stackrel{z}{opposite}\\&#10;\end{cases}\\\\\\ 6^2(\sqrt{2})^2=2z^2\implies 36(2)=2z^2\implies \cfrac{36(2)}{2}=z^2\implies 36=z^2&#10;\\\\\\&#10;\sqrt{36}=z\implies 6=z
4 0
3 years ago
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