In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
Answer:
about 3 seconds
Step-by-step explanation:
hope this helps
Rule: if you have graph of function y=f(x) and a>0, then:
1. y=f(x-a) is translation a units right;
2. y=f(x+a) is translation a units left;
3. y=f(x)-a is translation a units down;
4. y=f(x)+a is translation a units up;
Since g(x)=f(x+2)-5, then firstly you have to translate the graph of function y=f(x) two units left and secondly 5 units down.
Answer:
i am on this exact question and i am confused myself because it seems like the answer should be "180 degree rotation with a translation of 5 units to the right" but that is not an option :/ so my best guess is either A or D hope this helps at all
Step-by-step explanation:
Hello,
First we work out the equations:
x + y =62 will be the first equation.
2x= y +13 is the second equation.
We can first rewrite the second equation as 2x – y =13.
So we have:
x + y = 62
2x –y =13
KEEP IN MIND: With y being positive in one of the equations and negative in the other, we can combine the equations to quickly eliminate y and solve for x.
x + y = 62
+2x –y =13
3x = 75 divide both sides by 3 to get x.
x = 25
Now that we have x we can substitute the value for x, 25.
25 + y = 62 we can subtract 25 from both sides to get y.
y = 62- 25
y = 37
2(25) = 37 + 13
Therefore,
50 = 50
Have a amazing day.
