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ivanzaharov [21]
3 years ago
13

Which expression is equivalent to this equation

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0

Answer:

17-5

Step-by-step explanation:

lol XD I spent alot of time trying to answer this you better say thanks

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In basketball game,carolyn made 14 out of 20 shots anna made 16 out of 24 shots. explain how you can tell if the two players mad
Naddik [55]

Answer:

14/20 is simplified to 7/10. 16/24 is simplified to 2/3 they are not proportional.

Step-by-step explanation:

7 0
3 years ago
What’s the correct answer
Marta_Voda [28]
The second one is correct
6 0
3 years ago
Solve for x. (Round to the nearest thousandth.)<br> 3x - 8 = 15
saul85 [17]

Answer:x = 7.667

Step-by-step explanation:

3x - 8 = 15

     + 8 = 23

3x = 23

divide 3 by 3 and 23 so you get x by itself

answer = 7.667

3 0
3 years ago
Read 2 more answers
Explain two ways you could evaluate (f + g)(2).
natka813 [3]
To evalute anything you need expressions for f and g.
By definition of (f+g)(2)=f(2)+g(2) so you take each expression and evaluate them at 2. or you can use (f+g)(2) and calculate f+g and then evaluate whatever you get in 2.
7 0
3 years ago
In a recent Super Bowl, a TV network predicted that 53 % of the audience would express an interest in seeing one of its forthcom
rjkz [21]
<h3>Answer: -0.196</h3>

======================================================

Explanation:

We're conducting a one proportion Z test.

The hypothesized population proportion is p = 0.53, which is not to be confused with the p-value (unfortunately statistics textbooks seem to overuse the letter 'p'). Luckily this problem is not asking for the p-value.

The sample population proportion is

phat = x/n = 41/79 = 0.518987 approximately

The standard error (SE) is

SE = sqrt(p*(1-p)/n)

SE = sqrt(0.53*(1-0.53)/79)

SE = 0.056153 approximately

Making the test statistic to be

z = (phat - p)/(SE)

z = (0.518987 - 0.53)/0.056153

z = -0.19612487311452

z = -0.196

Which is approximate and rounded to 3 decimal places.

3 0
4 years ago
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